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Mass Transfer

1.0

Worked examples

Worked example: effect of doubling diffusivity on kLk_L

In notes →

Question. If the molecular diffusivity of a solute doubles while keeping all other physical parameters and film thickness constant, according to Whitman's film theory, the mass transfer coefficient kLk_L will:

  • (a) Increase by a factor of 1.411.41 (2\sqrt{2})
  • (b) Increase by a factor of 2.02.0
  • (c) Increase by a factor of 4.04.0
  • (d) Remain unchanged

Solution.

  1. Film theory gives kL=DAB/δk_L = D_{AB}/\delta — a linear relationship between kLk_L and DABD_{AB}, with δ\delta held fixed.
  2. Doubling DABD_{AB} (with δ\delta constant) doubles kLk_L directly: kL,new=(2DAB)/δ=2 (DAB/δ)=2 kL,oldk_{L,\text{new}} = (2D_{AB})/\delta = 2\,(D_{AB}/\delta) = 2\,k_{L,\text{old}}.
  3. A factor of 2\sqrt{2} (option a) is what penetration or surface renewal theory would predict instead, since those give kL∝DAB0.5k_L \propto D_{AB}^{0.5} — not film theory.

Answer: (b) — kLk_L increases by a factor of 2.02.0.

Worked example: interfacial area from bubble size

In notes →

Question. A sparger releases a fixed volume of gas as a single bubble of diameter 10 mm10\ \text{mm}. What is the interfacial area per unit volume (aa) for (a) that single bubble, and (b) the same total gas volume split instead into 100 equal smaller bubbles?

Solution.

  1. For a sphere, a=6/da = 6/d.
  2. Single bubble: d=10 mm=0.01 md = 10\ \text{mm} = 0.01\ \text{m}, so a=6/0.01=600 m2/m3a = 6/0.01 = 600\ \text{m}^2/\text{m}^3.
  3. Splitting a fixed total gas volume into nn equal bubbles scales aa by n1/3n^{1/3} (smaller diameter, more total surface for the same volume).
  4. For n=100n = 100: a=600×1001/3≈600×4.64≈2790 m2/m3a = 600 \times 100^{1/3} \approx 600 \times 4.64 \approx 2790\ \text{m}^2/\text{m}^3.

Answer: a≈600 m2/m3a \approx 600\ \text{m}^2/\text{m}^3 for the single bubble, rising to ≈2790 m2/m3\approx 2790\ \text{m}^2/\text{m}^3 once split into 100 smaller bubbles of the same total volume.

Worked example: electrolyte effects in a sparged bioreactor

In notes →

Question. Which of the following effects occur when pure electrolytes (salts such as NaCl or Na2_2SO4_4) are added to pure water in a sparged bioreactor? (a) Electrolytes inhibit bubble coalescence. (b) Mean bubble diameter decreases at high salt concentrations. (c) Interfacial area aa increases. (d) Oxygen solubility C∗C^* increases due to the salting-in effect.

Solution.

  1. Ions stabilize the thin film between approaching bubbles, preventing them from merging — (a) is correct.
  2. Coalescence inhibition means bubbles stay smaller instead of merging into larger ones as salt concentration rises — (b) is correct.
  3. Smaller dbd_b at roughly the same hold-up means a=6εg/dba = 6\varepsilon_g/d_b rises — (c) is correct.
  4. Electrolytes lower O2_2 solubility via salting-out, not raise it via "salting-in" — (d) gets both the direction and the name of the effect wrong.

Answer: (a), (b), and (c) are correct; (d) is false.

Worked example: which statements about interfacial area are correct

In notes →

Question. Select the CORRECT statements regarding the gas-liquid interfacial area per unit volume aa: (a) aa is related to gas hold-up (εg\varepsilon_g) and bubble diameter (dbd_b) by a=6εg/dba = 6\varepsilon_g/d_b. (b) High shear from Rushton turbines reduces mean bubble diameter, thereby increasing aa. (c) Increasing gas sparging velocity increases gas hold-up, generally increasing aa. (d) Coalescence of air bubbles increases aa.

Solution.

  1. (a) is exactly the general interfacial-area equation above — correct.
  2. Rushton turbines are high-shear radial impellers; that shear breaks bubbles into smaller ones, and since a∝1/dba \propto 1/d_b, a smaller dbd_b means a higher aa — (b) is correct.
  3. Higher sparging (superficial gas) velocity increases εg\varepsilon_g (more gas held up in the dispersion at any instant); with dbd_b roughly unchanged, a=6εg/dba = 6\varepsilon_g/d_b rises too — (c) is correct.
  4. Coalescence merges small bubbles into larger ones, increasing dbd_b. Since a∝1/dba \propto 1/d_b, this decreases aa — (d) is false; it directly contradicts (b) and (c), which both work by keeping bubbles small.

Answer: (a), (b), and (c) are correct; (d) is false.

Worked example: which theory does each statement describe?

In notes →

Question. Which of the following statements comparing mass transfer theories are correct?

  • (a) Whitman's film theory predicts kLk_L is directly proportional to DABD_{AB} raised to the power 1.01.0.
  • (b) Higbie's penetration theory predicts kLk_L is proportional to DABD_{AB} raised to the power 0.50.5.
  • (c) Danckwerts' surface renewal theory assumes all liquid elements stay at the interface for the exact same contact time.
  • (d) Both Higbie's and Danckwerts' theories predict kLk_L is proportional to DAB\sqrt{D_{AB}}.

Solution.

  1. Film theory models the film as a fixed-thickness, steady-state diffusion path: kL=DAB/δk_L = D_{AB}/\delta, which is linear in DABD_{AB}. (a) is correct.
  2. Higbie's kL=2DAB/(πtc)k_L = 2\sqrt{D_{AB}/(\pi t_c)} is a square-root dependence. (b) is correct.
  3. "Exact same contact time for every element" is Higbie's assumption, not Danckwerts' — Danckwerts specifically replaced it with a random distribution of surface ages. (c) is incorrect, since it describes the wrong theory.
  4. Danckwerts' kL=DAB sk_L = \sqrt{D_{AB}\, s} is also a square-root dependence, matching Higbie's. (d) is correct.

Answer: (a), (b), and (d) are correct; (c) is incorrect.

Worked example: which factors affect C∗C^*?

In notes →

Question. Which of the following physical factors influence the saturation dissolved oxygen concentration (C∗C^*) in a bioreactor?

  • (a) Partial pressure of oxygen in the inlet gas stream
  • (b) Total bioreactor headspace pressure
  • (c) Temperature of the broth
  • (d) Concentration of dissolved salts and sugars in the medium

Solution. All four are genuine factors, via C∗=pO2/HC^* = p_{O_2}/H:

  1. (a) sets pO2p_{O_2} directly. Correct.
  2. (b) sets pO2p_{O_2} indirectly, through Dalton's law (pO2=yO2Ptotalp_{O_2} = y_{O_2} P_{total}). Correct.
  3. (c) sets HH — higher temperature raises HH and lowers C∗C^*. Correct.
  4. (d) also sets HH, via the salting-out effect — dissolved solutes raise HH and lower C∗C^* relative to pure water. Correct.

Answer: all four, (a)–(d), influence C∗C^*.

Worked example: true/false on oxygen transfer fundamentals

In notes →

Question. Which of the following statements regarding oxygen transfer in aerobic bioreactors is/are TRUE?

  • (a) The driving force for oxygen transfer across the liquid film is (C∗−CL)(C^* - C_L).
  • (b) The addition of surfactants/antifoam agents generally decreases kLk_L by adding interfacial resistance.
  • (c) Smaller bubble size increases the gas-liquid interfacial area per unit volume aa.
  • (d) Dissolved oxygen saturation solubility C∗C^* increases with increasing temperature.

Solution.

  1. The film-theory rate equation is NA=kLa(C∗−C)N_A = k_L a (C^* - C) — the concentration gap between saturation and bulk is exactly the driving force. (a) is true.
  2. Antifoam agents are surfactants: they add a resistive film at the interface, lowering kLk_L. (b) is true.
  3. Smaller bubbles mean more total surface area for the same gas volume (a=6/da = 6/d for a sphere) — smaller dd gives larger aa. (c) is true.
  4. By Henry's law, C∗=pO2/HC^* = p_{O_2}/H, and HH increases with temperature (gas dissolution is exothermic) — so C∗C^* decreases with temperature, not increases. (d) is false.

Answer: (a), (b), and (c) are true; (d) is false.

Worked example: oxygen solubility claims

In notes →

Question. Select the CORRECT statements regarding oxygen solubility in aqueous fermentation broth: (a) O2_2 is a sparingly soluble gas, with C∗C^* typically around 77–9 mg/L9\ \text{mg/L} at 25 ∘C25\,^\circ\text{C} under ambient air. (b) Increasing bioreactor temperature increases C∗C^*. (c) Increasing vessel headspace pressure increases C∗C^* according to Henry's law. (d) High concentrations of dissolved electrolytes and sugars decrease C∗C^* via the salting-out effect.

Solution.

  1. (a) is the standard textbook solubility value for O2_2 in water at room temperature under air — correct.
  2. HH increases with temperature (gas dissolution is exothermic), so C∗=pO2/HC^* = p_{O_2}/H falls as temperature rises, not rises — (b) is false.
  3. Henry's law makes C∗C^* directly proportional to pO2p_{O_2}; raising headspace pressure raises pO2p_{O_2} (Dalton's law) and therefore C∗C^* — (c) is correct.
  4. Dissolved electrolytes and sugars raise the broth's effective HH (salting-out), which lowers C∗C^* — (d) is correct.

Answer: (a), (c), and (d) are correct; (b) is false.

Path of an oxygen molecule from a gas bubble to a cell's reaction site, numbered in eight steps: (1) interior of the bubble to the gas-liquid interface, (2) across the gas-liquid interface, (3) through the liquid film around the bubble, (4) across the bulk liquid, (5) through the liquid film around the cell, (6) across the liquid-cell interface, (7) to an individual cell within a clump, (8) through the cytoplasm to the reaction site — with k_L a labeling the overall path

Oxygen travels from a gas bubble to a cell's reaction site through eight resistances in series:

  1. Transfer from the interior of the bubble to the gas-liquid interface
  2. Transfer across the gas-liquid interface
  3. Diffusion through the liquid film around the bubble
  4. Transport through the bulk liquid
  5. Diffusion through the liquid film around the cell
  6. Movement across the liquid-cell interface
  7. For cells in a clump, diffusion to the individual cell
  8. Transport through the cytoplasm to the reaction site

Step 3 — diffusion through the liquid film around the bubble — is the largest resistance, which is why kLak_L a (built around that film) is the parameter that governs overall oxygen transfer.

This holds for free unicellular cells in well-mixed suspension, and rests on two other facts about the eight steps:

  • Step 2 (gas-film resistance) is negligible. O2_2 diffuses roughly four orders of magnitude faster in the gas phase than in the liquid phase, so for a sparingly-soluble gas like O2_2 almost all the resistance sits on the liquid side of the interface — this is why only the liquid-film coefficient (kLk_L) appears in kLak_L a, with no matching gas-film term.
  • Step 5 (liquid film around the cell) is negligible for small, free cells. A single bacterium or yeast cell is small enough, and its own mass-transfer coefficient high enough, that this film contributes almost nothing next to step 3 — don't confuse it with the bubble's film.

Exception: mycelial pellets. For filamentous fungi growing as pellets or clumps (step 7 in the list), O2_2 must additionally diffuse through the biomass matrix to reach cells at the core. Past a critical pellet radius, this intra-pellet diffusion resistance dominates instead — large enough pellets can starve their core of oxygen entirely (an anoxic core), even when kLak_L a at the bubble is perfectly adequate. So "the liquid film around the bubble is always the dominant resistance" is only true for free-cell suspensions, not pelleted or flocculated growth.

Worked example: which resistance dominates, and when

In notes →

Question. Which of the following statements about O2_2 transfer resistances from a gas bubble to a microbial cell in a stirred bioreactor are correct? (a) For unicellular bacteria in well-mixed suspension, the primary resistance is the liquid film around the gas bubble. (b) Gas-film resistance is practically negligible. (c) For fungal mycelial pellets, intra-pellet O2_2 diffusion is a significant resistance. (d) The liquid film around an individual bacterial cell is the dominant resistance for all aerobic bioprocesses.

Solution.

  1. For free unicellular cells, step 3 (liquid film around the bubble) is the largest of the eight resistances — (a) is correct.
  2. O2_2's gas-phase diffusivity is far higher than its liquid-phase diffusivity, so the gas film (step 2) contributes negligible resistance — (b) is correct.
  3. Mycelial pellets add an extra resistance step not present for free cells: diffusion through the pellet's own biomass to reach interior cells, which becomes dominant past a critical pellet size — (c) is correct.
  4. (d) conflates two different films: the film around the cell (step 5, negligible for small free cells) with the film around the bubble (step 3, the actual dominant resistance) — and ignores that pellets shift the dominant resistance elsewhere entirely. "For all aerobic bioprocesses" is false.

Answer: (a), (b), and (c) are correct; (d) is false.

Worked example: which changes raise kLak_L a?

In notes →

Question. Which of the following operational modifications will result in an increase in kLak_L a in an agitated bioreactor? (a) Increasing the impeller rotational speed (NiN_i) (b) Increasing the sparging gas flow rate (c) Adding a chemical antifoam agent at high concentration (d) Replacing a large single orifice sparger with a sintered microsparger.

Solution.

  1. Higher impeller speed increases turbulence and breaks bubbles smaller — kLak_L a increases. (a) is correct.
  2. Higher gas flow rate means more gas hold-up and more total interfacial area — kLak_L a increases. (b) is correct.
  3. High-concentration antifoam promotes coalescence and adds interfacial resistance, both of which lower kLak_L a rather than raise it. (c) is incorrect.
  4. A sintered microsparger produces much finer bubbles than a large single orifice, raising aa — kLak_L a increases. (d) is correct.

Answer: (a), (b), and (d) increase kLak_L a; (c) decreases it.

Worked example: which factors decrease kLak_L a

In notes →

Question. Which of the following factors will cause a DECREASE in kLak_L a in an agitated fermenter? (a) Addition of excess chemical antifoam agents (b) Increase in broth apparent viscosity due to mycelial fungal growth (c) Increasing the agitation speed from 200200 rpm to 500500 rpm (d) Coalescence of smaller gas bubbles into larger bubbles.

Solution.

  1. Excess antifoam promotes coalescence and adds its own interfacial resistance — both lower kLak_L a — (a) decreases it.
  2. Higher viscosity increases resistance to oxygen transfer, lowering kLak_L a — (b) decreases it.
  3. kLak_L a increases directly with stirrer speed — raising rpm from 200200 to 500500 increases kLak_L a, it doesn't decrease it — (c) is not a decreasing factor.
  4. Coalescence increases dbd_b, which lowers aa and therefore kLak_L a — (d) decreases it.

Answer: (a), (b), and (d) decrease kLak_L a; (c) increases it instead.

Worked example: what the off-gas balance method does and doesn't need

In notes →

Question. Select the CORRECT statements regarding the off-gas oxygen balancing method for measuring OTR: (a) It is a non-invasive, continuous method that can be applied during active fermentation. (b) It requires accurate measurement of inlet and exit gas flow rates and gas compositions. (c) It depends heavily on knowing the exact value of the liquid film thickness. (d) If respiratory quotient (RQ) is close to 11, inlet and outlet total volumetric gas flow rates are nearly equal.

Solution.

  1. The method only samples gas streams, never the broth, and runs continuously without interrupting the process — (a) is correct.
  2. The defining equation needs exactly FgF_g and CAGC_{AG} on both the inlet and outlet sides — (b) is correct.
  3. Film thickness is a film-theory construct behind kLk_L, not something this macroscopic gas-phase mass balance ever measures — (c) is false.
  4. RQ≈1RQ \approx 1 means moles of O2_2 consumed ≈\approx moles of CO2_2 produced, so the total gas-phase mole (and volumetric flow) count barely changes between inlet and outlet — (d) is correct.

Answer: (a), (b), and (d) are correct; (c) is false.

Worked example: which assertions about the respiring-cells variant are correct?

In notes →

Question. Select the CORRECT assertions regarding the dynamic gassing-out method (Variant A, with a respiring culture) for determining kLak_L a:

  • (a) The broth is first de-oxygenated by sparging nitrogen gas.
  • (b) Dissolved oxygen is monitored as a function of time after air sparging is resumed.
  • (c) The slope of ln⁡[(C∗−C)/C∗]\ln[(C^* - C)/C^*] versus time yields kLak_L a.
  • (d) The method cannot be applied if living, respiring microorganisms are present.

Solution.

  1. In this variant, de-oxygenation comes specifically from the culture's own respiration once air is cut off — nitrogen sparging belongs to Variant B, not this one. (a) is incorrect here.
  2. This is exactly the recovery phase the method measures: air resumes and CALC_{AL} is tracked climbing back up. (b) is correct.
  3. The correct ratio uses CˉAL\bar{C}_{AL} (the level actually reached under respiration), not CAL∗C^*_{AL} (the no-consumption saturation value) — see the distinction above. (c) is incorrect as stated.
  4. The opposite is true: this variant is specifically designed to be used with a living, respiring culture. (d) is incorrect.

Answer: (b) only.

Worked example: correctness checks across both variants

In notes →

Question. Regarding the dynamic gassing-out method for determining kLak_L a in a fermenter, which of the following statements is/are CORRECT? (a) De-oxygenation of the broth is achieved by sparging nitrogen gas or shutting off aeration while respiring cells consume oxygen. (b) The slope of the line obtained by plotting ln⁡[(C∗−C1)/(C∗−C2)]\ln[(C^*-C_1)/(C^*-C_2)] against (t2−t1)(t_2-t_1) during re-aeration directly yields kLak_L a. (c) If the DO probe response time (τp\tau_p) is comparable to or larger than 1/kLa1/k_L a, probe lag must be corrected. (d) The method cannot be used if the liquid broth contains dissolved salts.

Solution.

  1. Both routes are real — they're just the two different named variants above (respiring-cells vs. nitrogen-stripping), not two options within a single technique. (a) is correct as a statement about the method family as a whole.
  2. This is the two-point slope form of the recovery curve. Note that C∗C^* here is only literally exact for Variant B (nitrogen-stripped); for Variant A the correct baseline is CˉAL\bar{C}_{AL}, not the true C∗C^* (see above). Read at the level this question intends, the underlying "slope of ln⁡(driving force)\ln(\text{driving force}) vs. time" technique is what yields kLak_L a either way. (b) is correct, with that caveat in mind.
  3. A slow DO probe can't track the true recovery curve once its own response time approaches the process time scale 1/kLa1/k_L a, so its lag must be corrected for — (c) is correct.
  4. Dissolved salts are present in essentially every real fermentation broth and don't interfere with this method — (d) is false.

Answer: (a), (b), and (c) are correct; (d) is false — but remember which baseline (C∗C^* vs. CˉAL\bar{C}_{AL}) is actually correct depends on which variant you're running.

Worked example: catalyst and reaction order in the sulphite method

In notes →

Question. During kLak_L a measurement by the sulphite oxidation method, sodium sulphite is converted to sodium sulphate in the presence of a catalyst. The catalyst commonly used and the reaction order with respect to sulphite at moderate concentrations are: (a) Cu2+^{2+}, first-order (b) Co2+^{2+}, zero-order (c) Fe2+^{2+}, second-order (d) Zn2+^{2+}, half-order.

Solution.

  1. Co2+^{2+} (cobaltous sulphate) is a standard catalyst for this reaction, alongside Cu2+^{2+} — rules out (c) and (d), which use catalysts not associated with this method.
  2. The method's validity depends on the reaction being fast enough to never be rate-limiting: at moderate-to-high sulphite concentrations, the rate is independent of sulphite concentration — zero-order.
  3. (a) pairs a valid catalyst with the wrong order (first-order would make the reaction rate-limiting, defeating the method's purpose) — so only (b) pairs a valid catalyst with the correct kinetics.

Answer: (b) Co2+^{2+}, zero-order.

15 examples